Past Papers’ Solutions | Cambridge International Examinations (CIE) | AS & A level | Mathematics 9709 | Pure Mathematics 2 (P2-9709/02) | Year 2002 | Oct-Nov | (P2-9709/02) | Q#5
Question
The angle x, measured in degrees, satisfies the equation
i. By expanding each side, show that the equation may be simplified to
ii. Find the two possible values of x lying between and
.
iii. Find the exact value of , giving your answer as a fraction.
Solution
i.
We are given;
We apply following two addition formulae on both sides of given equation.
Therefore;
Since;
ii.
We are required to find the two possible values of x lying between and
.
We have found an equation in (i) as;
We can rearrange the equation as follows to solve it.
We know that ,therefore;
Using calculator we can find the value of .
Properties of |
|
Domain |
|
Range |
|
Periodicity |
|
|
|
Odd/Even |
|
Translation/ Symmetry |
|
|
We utilize the periodicity/symmetry property of to find other solutions (roots) of
:
Therefore;
For;
|
|
|
|
|
|
|
|
Only following solutions (roots) are within the given interval ;
|
|
iii.
We are required to find the exact value of , giving your answer as a fraction.
Therefore;
Hence, we need exact values of and
.
Expression for trigonometric ratio in right-triangle is;
We have already found in (ii) that;
Therefore, for this right-triangle;
Pythagorean Theorem
Now we have a right-angled triangle with;
|
|
|
|
|
|
|
|
|
|
Now we can substitute these values in the equation;