Past Papers’ Solutions | Cambridge International Examinations (CIE) | AS & A level | Mathematics 9709 | Pure Mathematics 1 (P1-9709/01) | Year 2019 | Oct-Nov | (P1-9709/11) | Q#7

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Question

The functions f and g are defined by

 for

 for .


i.       
Find the range of f and the range of g.

   ii.       Find an expression for fg(x), giving your answer in the form  , where a, b and c are  integers.

 iii.      Find an expression for , giving your answer in the same form as for part (ii).

Solution


i.
 

The given function is for .

Therefore, domain of  is;

For range of we substitute extreme value(s) of the domain in the function to get the extreme values of the range of the function.

It is evident that variable quantity in the given function is . It can assume any value based on  . For the minimum possible value of the will be minimum and consequently will assume the maximum possible value. 

Therefore, if ;

Since, , .

Similarly, for the maximum possible value of the will be maximum and consequently will assume the maximum possible value which will be always greater than ZERO.

Hence, the rage of  for  is;

The given function is for .

Therefore, domain of  is;

For range of we substitute extreme value(s) of the domain in the function to get the extreme values of the range of the function. 

It is evident that variable quantity in the given function is . It can assume any value based on .

For the minimum possible value of the will be maximum and consequently will assume the maximum possible value. 

Therefore, if

However, since ;

Similarly, for the maximum possible value of the will be minimum and consequently will assume the minimum possible value. 

Hence, the rage of  for  is;


ii.
 

We are given;

for

for

We are required to find the rage of function .

First, we find expression for ;

 iii.
 

Next, we find .

We have found above that;

We write it as;

To find the inverse of a given function we need to write it in terms of rather than in terms of .

Interchanging ‘x’ with ‘y’;

 

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