Past Papers’ Solutions | Cambridge International Examinations (CIE) | AS & A level | Mathematics 9709 | Pure Mathematics 1 (P1-9709/01) | Year 2016 | Oct-Nov | (P1-9709/12) | Q#2
Question
i. Express the equation in the form
, where k is a constant.
ii. Hence solve the equation for .
Solution
i.
We are given that;
We know that , therefore;
Comparison with given yields;
ii.
We are required to solve for
.
From (i) we know that can be written in the form;
Therefore, we solve for
.
To solve this equation for , we can substitute
. Hence,
Since given interval is , for
interval can be found as follows;
Multiplying the entire inequality with 2;
Since ;
Hence the given interval for is
.
To solve equation for interval
,
Using calculator we can find the value of .
Properties of are listed below.
Properties of |
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Periodicity |
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Odd/Even |
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Translation/ Symmetry |
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We utilize the periodic property of to find other solutions (roots) of
.
Therefore;
For;
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Only following solutions (roots) are within the given interval ;
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Since ;
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Therefore;
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Hence, all the solutions of the equation within the interval for
are;
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