Past Papers’ Solutions | Cambridge International Examinations (CIE) | AS & A level | Mathematics 9709 | Pure Mathematics 1 (P1-9709/01) | Year 2016 | Oct-Nov | (P1-9709/11) | Q#6
Question
i. Show that .
ii. Hence, or otherwise, solve the equation for
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Solution
i.
We have the trigonometric identity;
From this we can substitute ;
Hence, L.H.S=R.H.S.
ii.
We are required to solve the equation for
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From (i) we know that;
Substituting this in the given equation to solve;
We have the trigonometric identity;
From this we can substitute ;
Now we have two options.
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Again we have two options.
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Since we are required to solve the equation for
, we find other solutions as well within the given range.
We utilize the periodic property of to find another solution (root) of
:
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Symmetry |
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Hence;
For |
For |
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Therefore, we have four solutions (roots) of the equation;
So we have four possible values of ,
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To find all the solutions (roots) within interval, we utilize the periodic property of
for both these values of
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Periodic |
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For the given case,
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For |
For |
For |
For |
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Now;
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Only following solutions (roots) of the equation are within
interval;
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