Past Papers’ Solutions | Cambridge International Examinations (CIE) | AS & A level | Mathematics 9709 | Pure Mathematics 1 (P1-9709/01) | Year 2015 | May-Jun | (P1-9709/11) | Q#7
Question
a) The third and fourth terms of a geometric progression are and
respectively. Find the sum to infinity of the progression.
b) A circle is divided into 5 sectors in such a way that the angles of the sectors are in arithmetic progression. Given that the angle of the largest sector is 4 times the angle of the smallest sector, find the angle of the largest sector.
Solution
a)
From the given information, we can compile following data about Geometric Progression (G.P);
Expression for Common Ratio () in a Geometric Progression (G.P) is;
For the given case;
Expression for the general term in the Geometric Progression (G.P) is:
For the 3rd term we can write;
Expression for the sum to infinity of the Geometric Progression (G.P) when or
;
For the given case;
b)
From the given information, we can compile following data about Arithmetic Progression (A.P);
Smallest angle will be the first term;
Largest angle will be the last (5th) term;
Sum of all the angle-sectors in a circle is .
Expression for the general term in the Arithmetic Progression (A.P) is:
For the 5th term we can write;
Expression for the sum of number of terms in the Arithmetic Progression (A.P) is:
For the given case;
This is the smallest angle; we know that largest angle is four times of the smallest angle i.e.
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