Past Papers’ Solutions | Assessment & Qualification Alliance (AQA) | AS & A level | Mathematics 6360 | Pure Core 1 (6360-MPC1) | Year 2009 | January | Q#1
Question
The points A and B have coordinates (1,6) and (5,-2) respectively. The mid-point of AB is M.
a. Find the coordinates of M.
b. Find the gradient of AB, giving your answer in its simplest form.
c. A straight line passes through M and is perpendicular to AB.
i. Show that this line has equation .
ii. Given that this line passes through the point (k, k+5) , find the value of the constant k.
Solution
a.
We are given points A and B with coordinates (1,6) and (5,-2) respectively and required to find the coordinates of their mid-point of M.
To find the mid-point of a line we must have the coordinates of the end-points of the line.
Expressions for coordinates of mid-point of a line joining points and
;
x-coordinate of mid-point of the line
y-coordinate of mid-point of the line
Therefore, for the given case;
x-coordinate of mid-point of the line
y-coordinate of mid-point of the line
Hence, coordinates of mid-point (M) of AB are (3,2).
b.
We are given points A and B with coordinates (1,6) and (5,-2) respectively and required to find the gradient of line AB.
Expression for slope (gradient) of a line joining points and
;
Therefore, for the given case;
c.
i.
We are given that a straight line, say , passes through M and is perpendicular to line AB.
We are required to write equation of line .
To find the equation of the line either we need coordinates of the two points on the line (Two-Point form of Equation of Line) or coordinates of one point on the line and slope of the line (Point-Slope form of Equation of Line).
From (a) we have coordinates of point M(3,2) but we need to find the slope of line .
We are given that line is perpendicular to line AB.
If two lines are perpendicular (normal) to each other, then product of their slopes and
is;
Therefore;
From (b) we have slope of the line AB as .
Hence;
Now with the coordinates of a point on line as M(3,2) and slope of the line
as
, we can write equation of line
.
Point-Slope form of the equation of the line is;
ii.
We are given that line passes through a point (k,k+5).
If a line passes through a point, then coordinates of this point must satisfy the equation of the line.
From (c:i) we have found equation of line ;
Therefore, for point (k,k+5), equation must satisfy.
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