Hits: 58

# Past Papers’ Solutions | Edexcel | AS & A level | Mathematics | Core Mathematics 1 (C1-6663/01) | Year 2008 | June | Q#9

Hits: 58   Question The curve C has equation , where k is a constant. a.   Find . Point A with x-coordinate  lies on C. The tangent to C at A is parallel to the line with equation  . Find b.   The value of k. c.   The value of y-coordinate of A. Solution a.   Gradient (slope) of […]

# Past Papers’ Solutions | Edexcel | AS & A level | Mathematics | Core Mathematics 1 (C1-6663/01) | Year 2008 | June | Q#4

Hits: 13   Question , a.   Differentiate to find  . Given that , b.   Find the value of x. Solution a.   We are required to differentiate; Rule for differentiation of  is: Rule for differentiation of  is: Rule for differentiation is of  is: b.   We are given that; We have found in (a) that; We are given that […]

# Past Papers’ Solutions | Edexcel | AS & A level | Mathematics | Core Mathematics 1 (C1-6663/01) | Year 2008 | January | Q#10

Hits: 55   Question The curve C has equation y=(x + 3)(x −1)2 . a.   Sketch C showing clearly the coordinates of the points where the curve meets the coordinate  axes. b.   Show that the equation of C can be written in the form y = x3 + x2 − 5x + k, where k is a […]

# Past Papers’ Solutions | Edexcel | AS & A level | Mathematics | Core Mathematics 1 (C1-6663/01) | Year 2008 | January | Q#9

Hits: 25   Question The curve C has equation y = f(x), x > 0, and . Given that the point P(4,1) lies on C, a.   find f(x) and simplify your answer. b.   Find an equation of the normal to C at the point P(4, 1). Solution a.   We are required to find f(x), when; We are also […]

# Past Papers’ Solutions | Edexcel | AS & A level | Mathematics | Core Mathematics 1 (C1-6663/01) | Year 2008 | January | Q#5

Hits: 39   Question a.   Write  in the form  where p and q are constants. Given that  , x > 0, b.   find  , simplifying the coefficient of each term. Solution a.   We are given; b.   We are given; We are required to find; Therefore; Rule for differentiation of  is: As demonstrated in (a); Therefore; Rule for differentiation […]