# Past Papers’ Solutions | Cambridge International Examinations (CIE) | AS & A level | Mathematics 9709 | Pure Mathematics 2 (P2-9709/02) | Year 2018 | May-Jun | (P2-9709/23) | Q#2

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**Question**

A curve has equation

** i. **Find the x-coordinate of the stationary point.

** ii. **Determine whether the stationary point is a maximum or minimum point.

**Solution**

i.

First we are required to find the x-coordinate of the stationary point of the curve.

A stationary point on the curve is the point where gradient of the curve is equal to zero;

Hence, gradient of the curve at stationary point must be ZERO.

We can find expression for gradient of the curve and equate it with ZERO to find the x-coordinate of the point.

Gradient (slope) of the curve is the derivative of equation of the curve. Hence gradient of curve with respect to is:

Therefore;

Rule for differentiation of is:

First we differentiate using Chain Rule.

If we define , then derivative of is;

If we have and then derivative of is;

Let , then;

For ;

Since , then;

Rule for differentiation of is:

Rule for differentiation of is:

Next we differentiate .

For ;

Hence;

Since at stationary point the gradient of the curve must be equal to ZERO.

ii.

Next we are required to determine the nature of these stationary points.

Once we have the x-coordinate of the stationary point of a curve, we can determine its nature, whether minimum or maximum, by finding 2^{nd }derivative of the curve.

Second derivative is the derivative of the derivative. If we have derivative of the curve as , then expression for the second derivative of the curve is;

We have already found;

Therefore;

Rule for differentiation of is:

First we differentiate using Chain Rule.

If we define , then derivative of is;

If we have and then derivative of is;

Let , then;

Rule for differentiation of is:

Since , then;

Rule for differentiation of is:

Rule for differentiation of is:

Rule for differentiation of is:

Next we differentiate .

Rule for differentiation of is:

Hence;

Once we have the coordinates of the stationary point of a curve, we can determine its nature, whether minimum or maximum, by finding 2^{nd }derivative of the curve.

We substitute of the stationary point in the expression of 2^{nd} derivative of the curve and evaluate it;

If or then stationary point (or its value) is minimum.

If or then stationary point (or its value) is maximum.

We have already found that the x-coordinates of stationary point is 9.

We substitute x-coordinate in second derivative expression of the curve obtained above.

Hence, it is a minimum point.

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